Two equal charges are situated on the x axis at 40.0 cm on either side of the or

Question

Two equal charges are situated on the x axis at 40.0 cm on either side of the origin as shown in the figure below. Location A is on the perpendicular bisector at a distance of 29.0 cm from the origin on the y axis.(Assume that the +x axis is directed to the right and the +y axis is directed up.)

(a) If

q1 = ?4.75 ?C

and

q2 = ?4.75 ?C,

what is the net electric field due to both charges at location A? Express your answer in vector form.

(b) If

q1 = 2q2 (where q2 = ?4.75 ?C),

what is the net electric field at location A due to both charges? Express your answer in vector form.

I am working on in still but am not coming to this conclusion.

Two equal charges are situated on the x axis at 40.0 cm on either side of the origin as shown in the figure below. Location A is on the perpendicular bisector at a distance of 29.0 cm from the origin on the y axis.(Assume that the +x axis is directed to the right and the +y axis is directed up.) Two equal charges are situated on the x. I am working on in still but am not coming to this conclusion. Two equal charges are situated on the x. and on B they are getting So for A they are getting (b) If q1 = 2q2 (where q2 = ?4.75 ½C), what is the net electric field at location A due to both charges? Express your answer in vector form. (a) If q1 = ?4.75 ½C and q2 = ?4.75 ½C, what is the net electric field due to both charges at location A? Express your answer in vector form.

Explanation / Answer

q1 creates a field to the left and q2 creates a to the right. So their fields will subtract

E = k*(q2/r2^2 - q1/r1^2)

= 9.0x10^9*(4.75x10^-9/0.29^2

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