1.) A solid ball of mass 1.20kg and diameter 20.0cm is rotating about its diamet

Question

1.) A solid ball of mass 1.20kg and diameter 20.0cm is rotating about its diameter at 75.0rev/min. What is its kinetic energy ?

2.) If an additional 1.60J of energy are supplied to the rotational energy, what is the new angular speed of the ball in radians/sec?

1.) A solid ball of mass 1.20kg and diameter 20.0cm is rotating about its diameter at 75.0rev/min. What is its kinetic energy ? 2.) If an additional 1.60J of energy are supplied to the rotational energy, what is the new angular speed of the ball in radians/sec?

Explanation / Answer

I = 2/5 * M R2 , k = 1/2 I w2 = M R2 w2 / 5

k = 1/5 (1.20) * 0.12 (75 * 2pi / 60)2

= 0.148 J

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(1.748/0.148) = (w^2)/(75^2)

w = 258 rev/min

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