Another Source of Magnetic Field The figure (Figure 1) shows the charging of a p

Question

Another Source of Magnetic Field The figure (Figure 1) shows the charging of a parallel- plate capacitor whose plates are circular, of radius 4.00cm At the instant depicted, there is a current of 0.284A in the capacitors Ieads. Part A Find the magnitude of the rate of change of the electric field between the plates. Assume the plates? separation is small compared to their radius. Part B What is the magnitude of the magnetic field between the plates at a distance 1.01cm from the capacitor?s axis?

Explanation / Answer

A) I = dq /dt    = 0.284
dq /dt = 0.284 C
and C = e0 *A /d

and using , Q = CV
dq / dt = C dv/dt
dq / dt    = (e0 *A /d) dv/dt   = e*A d(v/d) / dt   = e*A dE / dt
dE/dt   = 0.284 / (8.854 x10-12x(pi x 0.04^2))   = 6.38 x 10^12 V/m.s

B) B = u0 * I / 2pi*R
B = 4pi x10-7 x 0.284 / 2pi x0.0101
B = 5.62 x 10-6 T

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