As shown below, a square loop of wire of side a moves through a uniform and cons
ID: 1259990 • Letter: A
Question
As shown below, a square loop of wire of side a moves through a uniform and constant magnetic field of magnitude B perpendicular to the page at constant velocity it directed to the right. Judd says that the emf induced in the loop is zero. Roger Claims that it has magnitude Blv. Which one, if either, is correct, and why? 2.The diagram below shows the position of a long straight wire perpendicular to the page and a set of direction labeled A through H 3. The path of a charged particle initially moving parallel to a uniform magnetic field will be a:Explanation / Answer
1.
Here , as the flux through the loop is constant , hence ,
the induced EMF is 0 .
correct option is a)
2.
Here , for current out of page , using right hand rule ,
the direction of field is C (vertically upwards)
3.
Here as velocity and field are parallel
the force acting on the particle is zero,
therefore , the path is straight line
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