(a) If the switch is thrown to the left (connecting the battery), how much time
ID: 1260074 • Letter: #
Question
(a) If the switch is thrown to the left (connecting the battery), how much time elapses before the current reaches 220 mA?
_________ ms
(b) What is the current in the inductor 10.0 s after the switch is closed?
________ A
(c) Now the switch is quickly thrown from a to b. How much time elapses before the current falls to 160 mA?
_________ ms
Explanation / Answer
Part A)
Apply I = E/R(1 - e-Rt/L)
.220 = (6/4.6)(1 - e-4.6t/.140)
t = 5.62 ms
Part B)
I = E/R(1 - e-Rt/L)
I = (6/4.6)(1 - e-4.6(10)/(.140)
I = 1.30 Amps
Part C)
I = E/R(e-Rt/L)
.160 = (6/4.6)(e-4.6t/.140)
t = 63.9 ms
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