A stream of protons and electrons are shot horizontally (from the left edge of t

Question

A stream of protons and electrons are shot horizontally (from the left edge of the page to the right) with a speed of 1.2X10^6 m/s. A magnetic field is oriented perpendicular to this motion (upward, out of page) with a magnitude of 1.225 T. What is the radius of curvature and the direction for the curvature that each of these particles undergoes?
A stream of protons and electrons are shot horizontally (from the left edge of the page to the right) with a speed of 1.2X10^6 m/s. A magnetic field is oriented perpendicular to this motion (upward, out of page) with a magnitude of 1.225 T. What is the radius of curvature and the direction for the curvature that each of these particles undergoes?

Explanation / Answer

apply centriipetal force = magnetic force

mv^2/r = qvB

r = mv/qB

so for proton

m = 1.67*10^-27 kgs

q = 1.6*10^-19 C

thus

r = 1.67*10^-27* 1.2*10^6/(1.6*(10^-19)* 1.225

r = 10.22 mm or 0.0102m   clcokwise

for eelctron

m = 9.11*10^-31 Kgs

so

r = 9.11*10^-31* 1.2*10^6/(1.6*10^-19* 1.225)

r = 5.577 *10^-5 m or 0.055 mm   anti clock wise

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