A) what is peak voltage B) what is the rms value of the current in this circuit

Question

A) what is peak voltage B) what is the rms value of the current in this circuit C)what is the average power consumed on the heating element D) write the equation for instantaneous voltage The figure shows variation of the current through the heating element with time in an iron when it is plugged into a standard 140V, 50 Hz outlet. A) what is peak voltage B) what is the rms value of the current in this circuit C)what is the average power consumed on the heating element D) write the equation for instantaneous voltage

Explanation / Answer

Note that

peak voltage = Vrms * sqrt(2)

Thus, as Vrms = 140 V,

Peak voltage = 198 V   [ANSWER, PART A]

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Here, the amplitude I max= 10 A. As

Irms = Imax / sqrt(2)

Then

Irms = 7.07 A [ANSWER, PART B]

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Note that

Pave = Irms Vrms

Thus,

Pave = 990 W    [ANSWER, PART C]

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Note that the voltage has exactly the same phase as the current here. Thus,

V(t) = Vmax sin(2 pi f t)

Thus,

V(t) = 198 sin (314.16t) V   [ANSWER, PART D]

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