I am SOconfused on how to do these. Can you please walk me through these step by
ID: 1260601 • Letter: I
Question
I am SOconfused on how to do these. Can you please walk me through these step by step so I know how to actually do them please. I realllllllyyy appreciate it!
A Chapters 5 and 13 Home C Chegg Study | Guided Soli xUMy.SUNYUlster.edu Portal x -> www.webassign.net/web/Student/Assignment-Responses/submit?dep-10539578 15. +-2.5 points HRW9 5.P.050.GO y Notes Ask Your Teacher In the figure below, three ballot boxes are connected by cords, one of which wraps over a pulley having negligible friction on its axle and negligible mass. The three masses are mA 22.0 kg, me = 41.0 kg, mc = 16.0 kg (a) When the assembly is released from rest, what is the tension in the cord connecting B and C? Select (b) How far does box A move in the first 0.250 s (assuming it does not reach the pulley)? Select GO Tutorial Read the eBook Section 5- Applying Newton's Laws Submit AnswerSave Progress Practice Another Version 16. + -3 points HRW10 5.P.053 My Notes Ask Your Teacher In the figure below, three connected blocks are pulled to the right on a horizontal frictionless table by a force of magnitude T3 = 70.8 N T] Ts (a) If m1 = 11.5 kg, m2 = 23.5 kg, and m3 = 30.5 kg, calculate the magnitude of the acceleration of the system m/s (b) Calculate the tension T1 (c) Calculate the tension T2 Additional Materials Section 5.3 Algebra-Squareroots & Squares 5:58 PM 3/18/2015Explanation / Answer
15) acceleration
a = (Mb+Mc)g / (Ma+Mb+Mc) = 57 g/79 = 7.07m/s2
a) T = Mc(g-a) = 16(9.8-7.1) =43.2N
b) X = 0.5 a t2 = 0.22 m
16) a)
acceleration a = T3/(m1+m2+m3) = 70.8/65.5 =1.08 m/2
b) T1 = m1 a = 11.5 x 1.08 =12.4 N
c) T2 = (m1+m2)a = 35x 1.08 =37.8N
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.