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Two large, parallel, metal plates carry opposite charges of equal magnitude. The

ID: 1260944 • Letter: T

Question

Two large, parallel, metal plates carry opposite charges of equal magnitude. They are separated by a distance of 40.0mm , and the potential difference between them is 370V .

Part A

What is the magnitude of the electric field (assumed to be uniform) in the region between the plates?

Part B

What is the magnitude of the force this field exerts on a particle with a charge of 2.90nC ?

F=.................. N

part C

Use the results of part (b) to compute the work done by the field on the particle as it moves from the higher-potential plate to the lower.

W= ......................J

Part D

Compare the result of part (c) to the change of potential energy of the same charge, computed from the electric potential.

Delta U = ...............J

Two large, parallel, metal plates carry opposite charges of equal magnitude. They are separated by a distance of 40.0mm , and the potential difference between them is 370V .

Part A

What is the magnitude of the electric field (assumed to be uniform) in the region between the plates?

E = 9250 N/C

Part B

What is the magnitude of the force this field exerts on a particle with a charge of 2.90nC ?

F=.................. N

part C

Use the results of part (b) to compute the work done by the field on the particle as it moves from the higher-potential plate to the lower.

W= ......................J

Part D

Compare the result of part (c) to the change of potential energy of the same charge, computed from the electric potential.

Delta U = ...............J

Explanation / Answer

PART A)

E=V/d

=370/40*10-3

=9250N/M

PARTB)

F=qE

=9250*2.9*10-9

=26.825*10-6N

PARTC)

W=F.d

=26.825*10-6*40*10-3

=1073*10-9J

PARTD)

W=q*V

=2.9*10-9*370

=1073*10-9

BOTH ARE SAME

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