An open U shaped tube (manometer) has a 1 cm 2 cross section opening. What volum

Question

An open U shaped tube (manometer) has a 1 cm2 cross section opening. What volume of water must be poured into the right tube to cause the mercury to rise 1 centimeters above its original position?

An on-farm diesel fuel tank is on a stand 4 feet above the ground. The tank is vented to the atmosphere (the air in the tank is at atmospheric pressure). If the diesel level in the tank is 2.6 feet above the release point. If the density of diesel is 6.98 pounds/gallon, what is the gauge pressure of the fuel at the nozzle? What is the absolute pressure?

Explanation / Answer

Here ,

let height of water be hw

for height of mercury , hm = 1 cm

equating gauge pressue

pw*g*hw = pm*g*hm

hw*1 = 13.6 * 1

hm = 13.6 cm

Now , volume of water = area* hm

volume of water = 1*13.6 =13.6 cm^3

the volume of water to be poured is 13.6 cm^3

B)

Here ,

Density = 6.98 pounds/gallon = 836.8 Kg/m^3

Now ,

gauge pressure Pg = p*g*h

pg = 836.8 * 9.8 * 2.6 * 0.3048

Pg = 6498.8 Pa

the gauge pressure is 6498.8 Pa

Now , P = Po+Pg

P = 6498.8 + 1.01 *10^5

P = 1.075 *10^5 Pa

the absolute pressure is 1.075 *10^5 Pa

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