A parallel-plate capacitor is charged to 5000 V. A proton is fired into the cent

Question

A parallel-plate capacitor is charged to 5000 V. A proton is fired into the center of the capacitor at a speed of 2.4

A parallel-plate capacitor is charged to 5000 V. A proton is fired into the center of the capacitor at a speed of 2.4 x10^5m/s as shown in (Figure 1) . The proton is deflected while inside the capacitor, and the plates are long enough that the proton will hit one of them before emerging from the far side of the capacitor. What is the impact speed of the proton? Express your answer to two significant figures and include the appropriate units.

Explanation / Answer

at centre V = 5000/2 = 2500 V

0.5*M*V^2 = e*V

0.5*1.67*10^-27 * (vf^2 - (2.4*10^5)^2) = 1.6*10^-19*2500

vf = 7.325*10^5 m/s

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