A jet of water squirts out horizontally from a hole near the bottom of the tank,

Question

A jet of water squirts out horizontally from a hole near the bottom of the tank, as seen in the figure.

Part A) Assume that x = 1.36 m and y = 1.71 m. What is the speed of the water coming out of the hole?

Part B) If the hole has a diameter of 3.66 mm, then what is the height, h, of the water level in the tank?

A jet of water squirts out horizontally from a hole near the bottom of the tank, as seen in the figure. Part A) Assume that x = 1.36 m and y = 1.71 m. What is the speed of the water coming out of the hole? Part B) If the hole has a diameter of 3.66 mm, then what is the height, h, of the water level in the tank?

Explanation / Answer

The time it takes to reach the bottom is

t = sqrt(2y/g) = 0.5907 s

Thus, the velocity of the squirting water is

vx = x/t = 2.30 m/s   [ANSWER, PART A]

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By Bernoulli's principle, h simplifies to

h = vx^2/2g

Thus,

h = 0.270 m   [ANSWER, PART B]

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