6. In Figure P20.63, mc rolling axle, 1.48 m long, is pushed along horizontal ra

Question

6. In Figure P20.63, mc rolling axle, 1.48 m long, is pushed along horizontal rails at a constant speed y = 6.00 m/s. A resistor R = 0396 Ohm is connected to the rails at points a and b, directly opposite each other. (The wheels make good electrical contact with the rails, and so the axle, rails, and R form a closed-loop circuit. The Only significant resistance in the circuit is R.) There is a uniform magnetic field B = 0.0700 T vertically downward. Figure P20.63 (a) Find the induced current I in the resistor. x A (b) What horizontal force F is required to keep the axle rolling at constant speed? x N (c) Which end of the resistor, a or b, is at the higher electric potential?

Explanation / Answer

a)

here,

as the induced EMF is

EMF = BVL

Using ohm's law

induced current = 6 *0.07 * 1.48/.396

induced current = 1.57 A

the induced current I is 1.57 A

b)

Now , magnetic force = BIL

magnetic force = 0.07 * 1.57 * 1.48

FOrce = 0.163 N

the force required to keep the velocity consant is 0.163 N

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