(a) What is the impulse of the force for this 4.30 s? kg An engine of the orbita

Question

(a) What is the impulse of the force for this 4.30 s?
kg

An engine of the orbital maneuvering system (OMS) on a space shuttle exerts a force of 25300 N j for 4.30 s, exhausting a negligible mass of fuel relative to the 95,000-kg mass of the shuttle. (a) What is the impulse of the force for this 4.30 s? kgm/s j (b) What is the shuttle's change in momentum from this impulse? kgm/s j (c) What is the shuttle's change in velocity from this impulse? m/s j (d) Why can't we find the resulting change in kinetic energy of the shuttle?

Explanation / Answer

If the mass of fuel exhausted is negligible in comparison with mass of the rocket then we can assume mass remains constant during the process.

F = dP/dt

Where F is the impulse of the force

Impulse = F dt

               = 25300*4.30

               = 108790 N-sec

b> dP = 108790 N-sec

c> m dv = 108790

dv = 108790/95000

dv = 1.14 m/sec

d> we can

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