- -Part A: Determine T 1, T 2, and T 3. -Part B: Determine ? E t h , W s , and Q

Question

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-Part A: Determine T1, T2, and T3.

-Part B: Determine ?Eth, Ws, and Q for 1?2.

-Part C: Determine ?Eth, Ws, and Q for 2?3.

-Part D: Determine ?Eth, Ws, and Q for 3?1.

-Part E: What is the engine

The heat engine shown in the figure uses 23 mol of a mon atomic gas as the working substance. Part A: Determine T1, T2, and T3. -Part B: Determine ?Eth, Ws, and Q for 1?2. -Part C: Determine ?Eth, Ws, and Q for 2?3. -Part D: Determine ?Eth, Ws, and Q for 3?1. -Part E: What is the engine??s thermal efficiency?

Explanation / Answer

Determine T1, T2, and T3.

Use PV = nRT

T1 = (400x10^3)(0.025) / 2.3(8.314) = 523K

T2 =  (600x10^3)(0.05) / 2.3(8.314) = 15688.6K

T3 = (400x10^3)(0.05) / 2.3(8.314) = 1046K

Determine ?Eth, Ws, and Q for 1?2.

The area under the graph is W = (1/2)(0.05 - 0.025) (600-400)x10^3 = 2.5kJ

Internal energy E = (3/2) (p2v2-p1v1)

=(3/2) (600x0.05 - 400x0.025)x10^3 = 30k J

Heat given Q = E+W = 2.5 + 30kJ = 32.5kJ

Determine ?Eth, Ws, and Q for 2?3.

W = 0 , E = (400x0.025 -600x0.05)x10^3 /(2.3-1) = - 15kJ

Q = -15kJ + 0 = -15kJ

Determine ?Eth, Ws, and Q for 3?1

W = -400x10^3 (0.25) = -10kJ

E = (400x0.25 - 600x0.05)x10^3 (2.3-1) = -15kJ

Q = -10kJ-15kJ = -25kJ

What is the engine

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