A rail gun uses electromagnetic forces to accelerate a projectile to very high v

Question

A rail gun uses electromagnetic forces to accelerate a projectile to very high velocities. The basic mechanism of acceleration is relatively simple and can be illustrated in the following example. A metal rod of mass 20.0g and electrical resistance 0.200?rests on parallel horizontal rails that have negligible electric resistance. The rails are a distance L = 6.00cm apart. (Figure 1) The rails are also connected to a voltage source providing a voltage of V = 5.00V .
The rod is placed in a vertical magnetic field. The rod begins to slide when the field reaches the value B = 6.53

A rail gun uses electromagnetic forces to accelerate a projectile to very high velocities. The basic mechanism of acceleration is relatively simple and can be illustrated in the following example. A metal rod of mass 20.0g and electrical resistance 0.200?rests on parallel horizontal rails that have negligible electric resistance. The rails are a distance L = 6.00cm apart. (Figure 1) The rails are also connected to a voltage source providing a voltage of V = 5.00V .
The rod is placed in a vertical magnetic field. The rod begins to slide when the field reaches the value B = 6.53

A rail gun uses electromagnetic forces to accelerate a projectile to very high velocities. The basic mechanism of acceleration is relatively simple and can be illustrated in the following example. A metal rod of mass 20.0g and electrical resistance 0.200?rests on parallel horizontal rails that have negligible electric resistance. The rails are a distance L = 6.00cm apart. (Figure 1) The rails are also connected to a voltage source providing a voltage of V = 5.00V . The rod is placed in a vertical magnetic field. The rod begins to slide when the field reaches the value B = 6.53?10?2T . Assume that the rod has a slightly flattened bottom so that it slides instead of rolling. Use 9.80m/s2 for the magnitude of the acceleration due to gravity. Part A Find ?s, the coefficient of static friction between the rod and the rails. Give your answer numerically. ?s = ________ Figure 1 of 1

Explanation / Answer

here ,

Using Ohm's law

V = IR

I = 5/.2 = 25 A

Now , magnetic force on the rod , Fm = BIL

Fm = 6.53 *10^-2 * 25 * 0.06

Fm = 0.09795 N

Now , for sliding

uS* mg = Fm

uS * 0.020 * 9.8 = 0.09795

uS = 0.5

the coefficient of friction is 0.5

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.