I need help calculating amps for each resistor using the loop rule. . R1 = 20 W

Question

I need help calculating amps for each resistor using the loop rule.

.

R1 = 20 W       R2 = 40 W        R3 = 60 W

R4= 80 W        R5= 100 W      R6= 100 W

R7= 80 W

I know how to use a graphing calculator to find the amps, once you have the right equations, but I keep messing up the equations, I think.

I have I1= I2 +I3 and I3=I4+ I5, that I know is correct, but the putting in the numbers is what causing me issues.

I need help calculating amps for each resistor using the loop rule. R1 = 20 W R2 = 40 W R3 = 60 W R4 = 80 W R5 = 100 W R6 = 100 W R7 = 80 W I know how to use a graphing calculator to find the amps, once you have the right equations, but I keep messing up the equations, I think. I have I1= I2 +I3 and I3=I4+ I5, that I know is correct, but the putting in the numbers is what causing me issues.

Explanation / Answer

Let current in R6 is i6

current in R4 is i4 ,

current in R3 is i3 ,

using KVL ,

9 - 20*(i6 + i4 + i3) - 40 * (i4 + i3) - 60 i3 = 0

20 i6 + 120 i3 + 40 i4 = 9   ----(1)

Using KVL ,

9 - 20*(i6 + i4 + i3) - (100 + 80) * i6 = 0

200 i6 + 20i3 + 20 i4 = 9   ---(2)

again ,

9 - 20*(i6 + i4 + i3) - 40 * (i4 + i3) - (80 + 100)*i4 = 0

20 i6 + 240 i4 + 60 i3 = 9   ---(3)

solving 1 , 2 , 3

i6 = 0.03686 A = 36.7 mA

i4 = 0.0626 A = 62.6 mA

i3 = 0.0188 A = 18.8 mA

Now , i1 = 36.7 + 62.6 + 18.8

i1 = 118.1 mA

i2 = i4 + i3 = 62.6 + 18.8

i2 = 81.4 mA

i5 = i4 = 62.6 mA

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