A worker wants to turn over a uniform 1100-Nrectangular crate by pulling at 53.0

Question

A worker wants to turn over a uniform 1100-Nrectangular crate by pulling at 53.0 ? on one of its vertical sides (the figure (Figure 1) ). The floor is rough enough to prevent the crate from slipping.

What pull is needed to just start the crate to tip? P-?

How hard does the floor push on the crate? N-?

Find the friction force on the crate. F-?

What is the minimum coefficient of static friction needed to prevent the crate from slipping on the floor?

?s = ? A worker wants to turn over a uniform 1100-Nrectangular crate by pulling at 53.0 ? on one of its vertical sides (the figure (Figure 1) ). The floor is rough enough to prevent the crate from slipping. What pull is needed to just start the crate to tip? P-? How hard does the floor push on the crate? N-? Find the friction force on the crate. F-? What is the minimum coefficient of static friction needed to prevent the crate from slipping on the floor? ?s = ?

Explanation / Answer

The three basic equations for static equilibrium in this case are:

Torque around the lower left corner of the block (this answers 1)

Ly Fsin? - Lx W / 2 = 0

1.5 *1100*sin53 -1.5 *W/2=0

W=1756.99 J
Forces on X and Y in center of mass (this answers 2 and 3)

N - Fcos? - W = 0 ; N= Fcos? + W= 2418.98

Fsin? - Fr = 0

Fr=Fsin?=878.49
The minimum static friction coefficient is given by

Fr = us N =
Fsin? = us (Fcos? + W)

us= (Fcos? + W)/Fsin? =2.75

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