What is the direction of the magnetic force on a positive charge that moves as s

Question

What is the direction of the magnetic force on a positive charge that moves as shown in each of the six cases shown in Figure 21.46?

(a)  --Direction-- to the left to the right upward downward into the page out of the page no force

(b)  --Direction-- to the left to the right upward downward into the page out of the page no force

(c)  --Direction-- to the left to the right upward downward into the page out of the page no force

(d)  --Direction-- to the left to the right upward downward into the page out of the page no force

(e)  --Direction-- to the left to the right upward downward into the page out of the page no force

A velocity selector in a mass spectrometer, like that shown in Figure 21.39, uses a 0.150 T magnetic field.

(a) What electric field strength is needed to select a speed of 3.90 ? 106 m/s?
V/m
(b) What is the voltage between the plates if they are separated by 1.00 cm?
kV

What is the direction of the magnetic force on a positive charge that moves as shown in each of the six cases shown in Figure 21.46? (a) --Direction-- to the left to the right upward downward into the page out of the page no force (b) --Direction-- to the left to the right upward downward into the page out of the page no force (c) --Direction-- to the left to the right upward downward into the page out of the page no force (d) --Direction-- to the left to the right upward downward into the page out of the page no force (e) --Direction-- to the left to the right upward downward into the page out of the page no force A velocity selector in a mass spectrometer, like that shown in Figure 21.39, uses a 0.150 T magnetic field. (a) What electric field strength is needed to select a speed of 3.90 ? 10^6 m/s? (b) What is the voltage between the plates if they are separated by 1.00 cm? kV

Explanation / Answer

There are 2 questions , So i am answering only 1st question.
Please post 2nd question in another link.

magnetic force = q ( v X B)

a)
q = +ve
V = v(-j) = -v j
B = Bk = b k

F = q ( - vj X Bk )    = - qvB i   = qvB ( -i)

so direction is = -i means towrads left.

b)q = +ve
V = v(+j) = v j
B = B i

F = q(vj X Bi) = qvB (-k)

so direction = -k   = into the page

c) q = +ve
V = v(+i) = v i
B = B (-k) = - B k

F = q(vi X -Bk) = qvB (j)

so direction = j   = upwards

d)
q = +ve
V = v(-i) = - v i
B = B (+i) = B i

F = q(- vi X Bi) = 0

so direction = No force

e)   q = +ve
V = v(-k) = -v k
B = B (j) = B j

F = q(-vk X Bj) = qvB (i)

so direction = i = towards right

f)
q = +ve
V = v(+k) = v k
B = B (-i) = - B i

F = q(vk X -Bi) = qvB (-j)

so direction = -j = downwards

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.