1-A tennis player swings her 1000g racket with a speed of 10m/s. She hits a 60g

Question

1-A tennis player swings her 1000g racket with a speed of 10m/s. She hits a 60g tennis ball that was approaching her at a speed of 20m/s. The ball rebounds in the opposite direction at 40m/s.

How fast is the racket moving immediately after the impact? (You can ignore the interaction of the racket with her hand during the brief duration of the collision)

What was the impulse given to the ball?

If the tennis ball and the racket are in contact for 10ms what was the average force of the racket on the ball during the collision?

Explanation / Answer

conservation of momentum:

Mtut + Mbub = Mtvt + Mbvb

1*10 + 0.06*-20 = 1* vt + 0.06*40

vt = 6.4 m/s (speed of racket)

Impulse = change in momentum

I = 0.06*( 40 - (-20))

I = 0.06*60

I = 3.6 N-sec

F*t = I

F*10*10-3 = 3.6

F = 360 N

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