Conductor A carries a current of 159 A and is held firmly in position. Conductor

Question

Conductor A carries a current of 159 A and is held firmly in position. Conductor B carries a current IB and is allowed to slide freely up and down (parallel to A) between a set of non-conducting guides. If the mass per unit length of conductor B is 0.120 g/cm, what value of current IB will result in equilibrium when the distance between the two conductors is 2.21 cm?

Two long, parallel conductors carry currents in the same direction, as shown in the figure below. Conductor A carries a current of 159 A and is held firmly in position. Conductor B carries a current IB and is allowed to slide freely up and down (parallel to A) between a set of non-conducting guides. If the mass per unit length of conductor B is 0.120 g/cm, what value of current IB will result in equilibrium when the distance between the two conductors is 2.21 cm?

Explanation / Answer

attraction force per unit length between wires = uo*i1*ib /2*pi*d
it should balance = mg
here mass per unit length = m = .12 g/cm = .00012 kg/.01 m = .012 kg/m

.012 x 9.81 = 2 x 10^-7 x 159 x Ib /.0221

Ib = 81.81 A

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