a)What is the total work W fric done on the block by the force of friction as th

Question

a)What is the total work Wfric done on the block by the force of friction as the block moves a distance 10.0m up the incline?

b)What is the total work WF done on the block by the applied force F?  as the block moves a distance 10.0m up the incline?

c)What is the total work Wfric done on the block by the force of friction as the block moves a distance 10.0m down the incline?

d)What is the total work WF done on the box by the applied force 70.0N in this case?

a)What is the total work Wfric done on the block by the force of friction as the block moves a distance 10.0m up the incline? b)What is the total work WF done on the block by the applied force F? as the block moves a distance 10.0m up the incline? c)What is the total work Wfric done on the block by the force of friction as the block moves a distance 10.0m down the incline? d)What is the total work WF done on the box by the applied force 70.0N in this case? A block of mass 1.00kg sits on an inclined plane as shown, (Figure 1) A force of magnitude 70.0N is pulling the block up the incline. The coefficient of kinetic friction between the plane and the block is 0.500. The inclined plane makes an angle 10.0 degrees with the horizontal.

Explanation / Answer

a) Wfri = Friction*d*cos(180)

= mue_k*m*g*cos(10)*d*(-1)

= -0.5*1*9.8*cos(10)*10

= -48.26 J

b) WF = F*d*cos(0)

= 70*10

= 700 J

c) same -48.26 J

d) same 700 J

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