The graph shows the US Department of Labor noise regulation for working without

Question

The graph shows the US Department of Labor noise regulation for working without ear protection. A machinist is in an environment where the ambient sound level is of 85 dB, i.e., corresponding to the 8 Hours/day noise level. The machinist likes to listen to music, and plays a Boom Box at an average level of 82.0 dB.

Please show work so I can understand how solution is acheived. I wish to understand to method of calculation. Thanks.

Part A) Calculate the INCREASE in the sound level from the ambient work environment level (in dB).

Part B) A student at a rock concert has a seat close to the speaker system, where the average sound intensity corresponds to a sound level of 118 dB. By what factor does that sound intensity exceed the 1- Hours/day intensity limits from the graph?

The graph shows the US Department of Labor noise regulation for working without ear protection. A machinist is in an environment where the ambient sound level is of 85 dB, i.e., corresponding to the 8 Hours/day noise level. The machinist likes to listen to music, and plays a Boom Box at an average level of 82.0 dB. Please show work so I can understand how solution is acheived. I wish to understand to method of calculation. Thanks. Part A) Calculate the INCREASE in the sound level from the ambient work environment level (in dB). Part B) A student at a rock concert has a seat close to the speaker system, where the average sound intensity corresponds to a sound level of 118 dB. By what factor does that sound intensity exceed the 1- Hours/day intensity limits from the graph?

Explanation / Answer

Increase in sound level is given by the slope of the graph.... The sound level is increases towards lowere hours/day...Its mean at hour/day approches to O intensity in sound level increases....Now this graph is showing the inverse relatioship between the sound level and hours per day.

   The slope of the graph shows the increase in sound level..

At 6hours/day the coresponding sound level is 87, while at 4hours per day it is 90, at 2hours/day it is 95,1hour/day it is 100 and at 0.75hours/day it is 105.

   The average increase = 85+87+90+95+100+105 / 8+6+4+2+0

= 28.1db/hour/day

Part B) 118/28.1

   =4.1

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