A 7.33 g bullet is fired vertically into a 1.41 kg block of wood. The bullet get

Question

A 7.33 g bullet is fired vertically into a 1.41 kg block of wood.

The bullet gets stuck in the block, and the impact lifts the block 0.71 m up. (That is, the block

A 7.33 g bullet is fired vertically into a 1.41 kg block of wood. The bullet gets stuck in the block, and the impact lifts the block 0.71 m up. (That is, the block ?? with the bullet stuck in it ?? rises 0.71 m up above its initial position, and then falls back down.) Given g = 9.8 m/s2. What was the initial velocity of the bullet? Answer in units of m/s

Explanation / Answer

Start by using conservation of energy...

PE = KE
mgh = .5mv2 (mass here cancels)

(9.8)(.71) = .5(v2)

v = 3.73 m/s

Then by conservation of momentum

mv = (M +m)v

(.00733)v = (1.41733)(3.73)

v = 721.3 m/s

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