1. What is the magnitude and direction (clockwise or counterclockwise) of the cu
ID: 1266254 • Letter: 1
Question
1. What is the magnitude and direction (clockwise or counterclockwise) of the current induced in the loop?
2.Calculate the magnitude of the external force Fext required to move the loop at a constant speed of v = 3.9 m/s. The mass of the loop is 0.008 kg.
In the figure, there is a uniform magnetic field of magnitude B = 1.5 T and directed into the plane of the paper in the region shown. Outside this region the magnetic field is zero. An 8 turn rectangular loop 0.20 m by 0.60 m and of resistance 9 ? is being pulled into the magnetic field by an external force, as shown. You MAY NOT simply start with ? = Blv (that is a derived equation)! 1. What is the magnitude and direction (clockwise or counterclockwise) of the current induced in the loop? 2.Calculate the magnitude of the external force Fext required to move the loop at a constant speed of v = 3.9 m/s. The mass of the loop is 0.008 kg.Explanation / Answer
1)
induced emf = N*B*dA/dt
= N*B*L*v
= 8*1.5*0.2*3.9
= 9.36 volts
induced current, I = induced emf Emf/R
= 9.36/9
= 1.04 A
direction : counter clockwise
2) F = N*B*I*L
= 8*1.5*1.04*0.2
= 2.496 N
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