A 71-kg water skier is being accelerated by a ski boat on a flat (\"glassy\") la

Question

A 71-kg water skier is being accelerated by a ski boat on a flat ("glassy") lake. The coefficient of kinetic friction between the skier's skis and the water surface is ?k = 0.27 . (Figure 1)

Part A

What is the skier's acceleration if the rope pulling the skier behind the boat applies a horizontal tension force of magnitude FT = 250N to the skier (? = 0?)?

Express your answer to two significant figures and include the appropriate units.

Part B

What is the skier's horizontal acceleration if the rope pulling the skier exerts a force of FT = 250N on the skier at an upward angle ? = 12??

Express your answer to two significant figures and include the appropriate units.

Explanation / Answer

A) F- u*N=m*a

or 250 - 0.27*71*9.81=71*a

or a=0.872 m/s^2

B)normal = mg- Fsin(12)

=644.53 N

so Fcos(12) - uN=ma

or 244.5 - 0.27*644.53 = 71*a

or a= 1 m/s^2

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