5. Consider a soot particle of kg that travels upward in a smokestack. Lets say

Question

5. Consider a soot particle of kg that travels upward in a smokestack. Lets say that a scrubber adds 69 electrons to the particle, and its charge was C, Assume the electric field in the scrubber is produced by two parallel, square plates of width L = 1.0 m and separation of d = 0.010 m, with charges . (a) What must be the value of the electric field between the plates so that force on the soot particle is equal to the weight of the particle? Hint: A real scrubber would use a collection of many pairs of such plates in parallel. (b) What charge Q on the scrubbers plates is required to produce the electric field in part (a)?

Explanation / Answer

a)

here you havent provided mass and charge

m=?

Q=?

Electric Force on soot particle

Fsoot=qsootE----1

Force due to soot particle weight

FW=msootg----2

1=2

qsootE=msootg

E=msootg/qsoot

b)

Electric filed between 2 metal scrubber plates with charge Q is

E=Q/eoA

Where area

A=L2=12=1 m2

Q=eoEA

where eo=8.85*10-12

E is from part A

substitute the values and get the answer

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