You wish to hit a target from several meters away with a charged coin having a m

Question

You wish to hit a target from several meters away with a charged coin having a mass of 4.4g and a charge of +2700?C . The coin is given an initial velocity of 12.0m/s , and a downward, uniform electric field with field strength 25.0N/C exists throughout the region.

Part A

If you aim directly at the target and fire the coin horizontally, what magnitude of uniform magnetic field are needed in the region for the coin to hit the target?

Express your answer using two significant figures.

PLEASE SHOW ALL WORK FOR POINTS AND RATING! Thanks!!!

Explanation / Answer

magnetic force = B*q*V
Initial velocity = 12 m/s
The magnetic force has to be upward to balance the electric force and weight of coin downward.
so, BqV = (q*E) + (m*g)
B* (2700 *(10^-6) *12) = (2700 * (10^-6) * 25) + (4.4* (10^-3) *9.8)
B =3.4141975 Tesla is the answer.

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