To determine the specific heat of an object, a student heats it to 100 ? C in bo

Question

To determine the specific heat of an object, a student heats it to 100 ? C in boiling water. She then places the 81.2g object in a 156g aluminum calorimeter containing 119g of water. The aluminum and water are initially at a temperature of 19.8 ?   , and are thermally insulated from their surroundings.

Part A

If the final temperature is 23.6 ?  , what is the specific heat of the object? ( J/(kg?K) )    

Part B

Referring to the table, identify the material in the object.

Substance Specific heat,
J/(kg?K) Water 4186 Beryllium 1820 Aluminum 900 Glass 837 Silicon 703 Iron (steel) 448 Copper 387 Silver 234 Gold 129 Lead 128

Explanation / Answer

Let the specific heat of the object be S

Heat lost by the object=Heat gained by water+Heat gained by Aluminium calorimeter

So

(81.2/1000)(S)(100-23.6)=(119/1000)(4186)(23.6-19.8)+(156)(900)(23.6-19.8)

Solving we get

S=391.127 J/Kg-K

Since it is nearer to 387,the given object is Copper

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