1)The distance between the first and fifth minima of a single-slit diffraction p

Question

1)The distance between the first and fifth minima of a single-slit diffraction pattern is 0.45 mm with the screen 50 cm away from the slit, when light of wavelength 531 nm is used.

(a) Find the slit width.
mm

(b) Calculate the angle ? of the first diffraction minimum.
rad

2)Monochromatic light of wavelength 357 nm is incident on a narrow slit. On a screen 3.00 m away, the distance between the second diffraction minimum and the central maximum is 1.00 cm.

(a) Calculate the angle of diffraction ? of the second minimum.

Explanation / Answer

1) a)

y = m lambda L/a

so

dy = dm lambda L/a

0.45E-3 = 4*531.0E-9*0.5/a

a=2.36 mm

b)

m lambda = d sin theta

theta =arcsin(531.0E-9/2.36E-3)= 2.25E-4 rad

2) a)

tan theta = y/L

theta = arctan(1.0E-2/3) = 0.19 degrees

b)

m lambda = d sin theta

d = 2*357.0E-9/sin(0.19 degrees)= 0.215 mm

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