Two rectangular pieces of plane glass are laid one upon the other on a table. A

Question

Two rectangular pieces of plane glass are laid one upon the other on a table. A thin strip of paper is placed between them at one edge, so that a very thin wedge of air is formed. The plates are illuminated at normal incidence by 541nm light from a mercury-vapor lamp. Interference fringes are formed, with 18.0fringes/centimeter .

Part A

Find the angle of the wedge.

Two rectangular pieces of plane glass are laid one upon the other on a table. A thin strip of paper is placed between them at one edge, so that a very thin wedge of air is formed. The plates are illuminated at normal incidence by 541nm light from a mercury-vapor lamp. Interference fringes are formed, with 18.0fringes/centimeter .

Part A

Find the angle of the wedge.

Explanation / Answer

Apply 2nt = m(wavelength)

2(1)(t) = 18(541 X 10-9)

t = 4.869 X 10-6 m

tan(angle) = t/L = 4.869 X 10-6/.01

angle = .0279o

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