PLEASE SHOW ALL WORK FOR EACH QUESTION!! You may need to use tables to answer th

Question

PLEASE SHOW ALL WORK FOR EACH QUESTION!!

You may need to use tables to answer the following question. All energy should be expressed in Joules. Remember that Q = m Delta T C, where C is the specific heat. A calorimeter contains 125.0 grams of water 22.0 degreeC. A small piece of metal with a mass of 40.0 grams is hanging in another beaker of boiling water, at 100 degreeC. The metal is removed from the boiling water an added to the cooler water in the calorimeter. The calorimeter cover is replaced and the metal and water eventually reach a final temperature 25.0 degreeC. What is the heat of the metal? A 160-gram sample of aluminum at 90.0 degreeC is placed in a Styrofoam container with 115 grams of water at 47 degreeC. A lid is placed on the container. No heat escapes to the environment and the heat gained by the Styrofoam is negligible. What is the final temperature of the water and aluminum?

Explanation / Answer

Part 1)

By conservation of energy, the hot metal loses energy and the water gains it

mc(delta T) = mc(delta T)

.04(c)(75) = (.125)(4186)(3)

c = 523.25 J/kg C

Part 2)

mc(delta T) = mc(delta T)

(.160)(900)(90 - Tf) = .115(4186)(Tf - 47)

12960 -144Tf = 481.39Tf - 22625.33

35585.33 = 625.39Tf

Tf = 56.9o

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