This is multiple choice question, i dont want people to guess so i left out the

Question

This is multiple choice question, i dont want people to guess so i left out the choices please answer the best you can.

1)

2)

A toy rocket is launched vertically from ground level (y = 0 m), at time t = 0.0 s. The rocket engine provides constant upward acceleration during the bum phase. At the instant of engine burnout, the rocket has risen to 64 m and acquired a velocity of 60 m/s. The rocket continues to rise in unpowered flight, readies maximum height, and falls back to the ground. The time interval, during which the rocket engine provides upward acceleration, is closest to: A toy rocket is launched vertically from ground level (y = 0 m), at time t = 0.0 s. The rocket engine provides constant upward acceleration during the bum phase. At the instant of engine burnout, the rocket has risen to 8I m and acquired a velocity of 40 m/s. The rocket continues to rise in unpowered flight, reaches maximum height, and falls back to the ground. The upward acceleration of the rocket during the burn phase is closest to: A toy rocket is launched vertically from ground level (y = 0 m), at time t = 0.0 s. The rocket engine provides constant upward acceleration during the bum phase. At the instant of engine burnout, the rocket has risen to 49 m and acquired a velocity of 60 m/s. The rocket continues to rise in unpowered flight, reaches maximum height, and falls back to the ground. The maximum height reached by the rocket is closest to:

Explanation / Answer

1.) a= v^2/2s = 60^2/(2*64) = 225/8 m/s^2

t = sqrt(2s/a) = sqrt(2*64/(225/8)) = 2.133 sec

2.) a = v^2/2s = 40^2/(2*81) = 800/81 = 9.87 m/s^2

3.) 0 - 60^2 = 2*(-9.8)*s

So s = 183.67 m

So max height = 49 + 183.67 = 232.67 m

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