1.The next problem is based on the velocity versus mass graph shown in the image

Q: 1.The next problem is based on the velocity versus mass graph shown in the image

a) Yeah, momentum would be p = mv = 2*(-0.5) kg m/s = -1kg m/s b) Option a) is correct, larger mass(-0.5m/s) moves towards left with smaller velocity than smaller mass(2m/s)

ID: 1272162 • Letter: 1

Question

1.The next problem is based on the velocity versus mass graph shown in the image below AFTER an explosion has occurred creating two masses (1kg and 2kg) .

http://tinypic.com/view.php?pic=m772j4&s=8#.U-EQQVZycpE

^^ pic ^^ What was the momentum of the large mass AFTER the explosion occurred?

Would it be p=mv >> = 2*(-0.5) = -1kgm/s?

2.The next problem is based on the velocity versus mass graph shown in the image below AFTER an explosion has occurred creating two masses (1kg and 2kg) ^^^^Same graph as above^^^^

Which motion map best describes the system after the explosion? Positive "x" is to the right. Reminder: arrows represent size and direction of velocity and each box is the size of the mass.

>>options>> http://tinypic.com/view.php?pic=ddymb5&s=8#.U-ER51ZycpE