In an LRC series circuit, the resistance is 320.0 ohms, the inductance is 0.350

Question

In an LRC series circuit, the resistance is 320.0 ohms, the inductance is 0.350 H, and the capacitance is 14.0 nanofarads.

(a) What is the resonance angular frequency of the circuit? 14285.71 Correct: Your answer is correct. rad/s

(b) The capacitor can withstand a peak voltage of 520.0 volts. If the EMF source operates at the resonance frequency, what maximum EMF amplitude can the source possibly have if the maximum capacitor voltage is not to be exceeded? V

I got a but don't know how to do part b

Explanation / Answer

B) At resonace impedance of inductor and capacitor are equal and opposite so they cancel out

Now what will be the current through circuit???

Suppose it can be V So current in circuit will be V/320 A

Now impedance of capacitor = 1/2*pi*f*C =1/(2*pi*14285.71*14*10^-9) = 795.775

So voltage across it will be (V/320)*795.775

It can be maximum 520V

So (V/320)*795.775 = 520

So V = 209.104V

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