Suppose you have two charged particles. If you triple the charge on one particle

Question

Suppose you have two charged particles. If you triple the charge on one particle and distance between the charges to 1/4 its previous value, how must the charge change on the other particle to allow the force between the two particles to double? You must decrease the charge on the other particle by a factor of 12. You must decrease the charge on the other particle by a factor of 16 You must leave the charge on the other particle unchanged You must increase the charge on the other particle by a factor of 6 You must decrease the charge on the other particle by a factor of 24

Explanation / Answer

apply F = kq1q2/r^2

Fnew = K (3q1) q2/r^2/16

Fnew = 48 K q1q2/r^2

so to double F = 48/2 = 24

option E it is

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