To learn about the Work-Energy Theorem and its basic applications. In this probl

Question

To learn about the Work-Energy Theorem and its basic applications.

In this problem, you will learn about the relationship between the work done on an object and the kinetic energy of that object.

The kinetic energy K of an object of mass mmoving at a speed v is defined as K=(1/2)mv2. It seems reasonable to say that the speed of an object--and, therefore, its kinetic energy--can be changed by performing work on the object. In this problem, we will explore the mathematical relationship between the work done on an object and the change in the kinetic energy of that object.

H answer:

Fnet = 12mv22?12mv12/s

I answer:

Wnet = Fnets

what is the answer for J.

Combine your results from Part H & Part I to find the net work Wnet done on the sled.

Explanation / Answer

Fnet = [(1/2)mv22 - (1/2)mv12?] *1/s (1)

where Fnet is the force applied v1 is initial velocity , v2 is final velocity and s is the displacement through which the force is applied.

we know that work

Wnet = Fnet *s

Wnet /s = Fnet ............(2)

putting value of Fnet from to (2) to (1)

Wnet /s = [(1/2)mv22 - (1/2)mv12?] *1/s

multiply both sides by 's' , we get

Wnet = [(1/2)mv22 - (1/2)mv12?]

this equation is the required work- energy relationship.

so work done ,

Wnet = [(1/2)mv22 - (1/2)mv12?]

Wnet /s = (m/2) (v22 - v12?)

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