I am not sure which equation I am supposed to use to find the current amplitude.
ID: 1273226 • Letter: I
Question
I am not sure which equation I am supposed to use to find the current amplitude. I had I=sq rt (2 x .34A) My professor said to check the equation. He also said that the .34A should not be under the square root sign
Find the average power delivered to the entire circuit. I am supposed to use the equation: average power=IrmsVrms cos(theta)=1/2 VI cos theta. I got 1.2 W but it's wrong.
The second question is: What is the average power delivered to the resistor? The answer is supposed to be .370 W
The third is: What is the average power delivered to the capacitor? The answer is also .370 W
Explanation / Answer
given that
current drqwn by a computer scanner I = 0.340A
voltage = V = 120v
frequency f = 60Hz
--------------------------------------
the power in the scanner P = VI
= 40.8W
resistance in the scanner R = V/I
= 352.9?
(a)
root mean square current Irms = ?P/R
= 0.34A
(b)
max current I max = Irms * ?2
= 0.480A
(c)
average current Iavg = 0.6366 * Imax
= 0.3055A
(d)
average square current = ( Irms)2
= 0.1156A
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