What would be the force between two 1.3-mm-diameter copper spheres 1.5cm apart?

Question

What would be the force between two 1.3-mm-diameter copper spheres 1.5cm apart? Assume that each copper atom has an equal number of electrons and protons. Suppose the magnitude of the proton charge differs from the magnitude of the electron charge by a mere 1 part in 10^9.

I've found the Mass of the copper balls I believe:

Then I divided the mass with the molecular weight:

Then I multiplied the amount of moles with 6.022 * 10^23:

Multiplied the amount of particles with the amount of valence electrons in a copper atom

And multiply that answer with e

so my charge for both spheres ended up being .448 C, and then I solved for F:

which is completly wrong and I don't understand what could have went wrong. I am surprised that a little bit of chemistry was thrown into it so I could have messed up in that general area, but please explain to me what I did wrong. Thank you

Explanation / Answer

since the charge of proton and electron differ , the repulsive force between proton-proton and electron-electron are not same.so that difference also adds to the answer.also the no. of valence electrons in Cu is 1.

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