tennis player hits a ball at ground level, giving it an initial velocity of 25.0
ID: 1275995 • Letter: T
Question
tennis player hits a ball at ground level, giving it an initial velocity of 25.0m/s at 56.0? above the horizontal.
Part A
What are the horizontal vh and vertical vv components of the ball's initial velocity?
Enter your answers separated by a comma.
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Term 1: Significant Figures Feedback: Your answer 13.98 m/s, m/s was either rounded differently or used a different number of significant figures than required for this part.
Term 2: Significant Figures Feedback: Your answer 20.73 m/s, m/s was either rounded differently or used a different number of significant figures than required for this part.
Part B
How high above the ground does the ball go?
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Significant Figures Feedback: Your answer 21.86 m was either rounded differently or used a different number of significant figures than required for this part.
Part C
How long does it take the ball to reach its maximum height?
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Part D
What is the ball's velocity at its highest point?
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Part E
What is the ball's acceleration at its highest point?
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Part F
For how long a time is the ball in the air?
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Significant Figures Feedback: Your answer 4.22 s was either rounded differently or used a different number of significant figures than required for this part.
Part G
When this ball lands on the court, how far is it from the place where it was hit?
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tennis player hits a ball at ground level, giving it an initial velocity of 25.0m/s at 56.0? above the horizontal.
Part A
What are the horizontal vh and vertical vv components of the ball's initial velocity?
Enter your answers separated by a comma.
vh, vv = 14.0,20.7 m/s, m/sSubmitMy AnswersGive Up
Correct
Term 1: Significant Figures Feedback: Your answer 13.98 m/s, m/s was either rounded differently or used a different number of significant figures than required for this part.
Term 2: Significant Figures Feedback: Your answer 20.73 m/s, m/s was either rounded differently or used a different number of significant figures than required for this part.
Part B
How high above the ground does the ball go?
h = 21.9 mSubmitMy AnswersGive Up
Correct
Significant Figures Feedback: Your answer 21.86 m was either rounded differently or used a different number of significant figures than required for this part.
Part C
How long does it take the ball to reach its maximum height?
t = 2.11 sSubmitMy AnswersGive Up
Correct
Part D
What is the ball's velocity at its highest point?
v = 14.0 m/sSubmitMy AnswersGive Up
Correct
Part E
What is the ball's acceleration at its highest point?
a = 9.80 m/s2SubmitMy AnswersGive Up
Correct
Part F
For how long a time is the ball in the air?
t = 4.23 sSubmitMy AnswersGive Up
Correct
Significant Figures Feedback: Your answer 4.22 s was either rounded differently or used a different number of significant figures than required for this part.
Part G
When this ball lands on the court, how far is it from the place where it was hit?
d = mSubmitMy AnswersGive Up
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Explanation / Answer
I'll start from where you left ! The only acceleration of ball is equal to 9.8m/s2 in vertically downward direction due to gravity. The ball does not experience any force in the horizontal direction and therby, no horizontal acceleration.
This means that horizontal component of velocity remains the same throughout the flight and is equal to initial horizontal velocity vh= 25cos56o=13.98m/s. The total time of flight (as calculated by you) is T=4.23 sec.
The horizontal distance travelled by it is thus d = vh * T =13.98*4.23= 59.13 metres.
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