A man is standing on a scale inside an elevator. As the elevator starts to go up

Question

A man is standing on a scale inside an elevator. As the elevator starts to go up with an acceleration a, the scale reads 836 N. The mass of the man is m = 70 kg.

(a) Which of the free body diagrams below displays all the forces acting on the man with the correct relative magnitudes and directions?

**** im having trouble uploading the image. please draw a free body diagram. the options I have are

1) a vertical line with a small vector on top(N) and a large vector on bottom(W)

2)a vertical line with two equal vectors (N)(W)

3) a vertical line with a large vector on top(N) and small vector on bottom(W)

4) two verical vectors upwards (N) and (ma). one downwards (W)

(b) Determine the acceleration of the elevator.

Explanation / Answer

actual reaing should be = 70*9.8 = 686N

but due to lift acceleration the force is 836N

so 70*x = 836

X = 11.94 m/sec^2

this is the effective accleration

X = 9.8 + lift acceleration

lift accleratin = 2.14 m/sec^2

option D is correct as the effective weight equal to normal reaction (N)(832N) is greater than actual weight(597.8)

yes

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