The position vector of an object in uniform circular motion about the origin of

Question

The position vector of an object in uniform circular motion about the origin of an XY coordinate system at a certain instant is given by r = (0.87i - 4.92 j)m. It is moving clockwise with a period of 9.8 s. The velocity vector is of the form v = (vxi + vyj) m/s NOTE: For the question below, the components of velocity could be positive, negative or zero. If negative, you must include the sign in your answer. 1. What is the x-component of the velocity (vx in m/s) at that instant? _________ Submit Answer Tries 0/1 2. What is the y-component of the velocity (vy in m/s) at that instant? ____________ Submit Answer Tries 0/1 3. What us the magnitude of the velocity (|v| in m/s) at that instant? ________ Submit Answer Tries 0/1 4. What is the dot product (v . r) of the velocity vector and the position vector at that instant? ____ Submit Answer Tries 0/1

Explanation / Answer

r    = 0.87 i -4.92 j

v = dr/dt = 0.87/9.8 i -   4.92/9.8 j

V = Vx i + Vyj    = 0.088 i - 0.502 j

1. Vx = 0.088 m/s
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2. Vy = -0.502 m/s
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3. mag of V^2 = 0.088^2 +(0.502^2)

V = 0.509 m/s
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4. v.r = 0.87 * 0.088 -(4.92*-0 .502)

v.r = 0.323

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