1. A box sits on top of a very slippery slide that starts at a height of 12 m of

Question

1. A box sits on top of a very slippery slide that starts at a height of 12 m off the ground. It then moves down the slide. If we assume there is no significant friction, how fast will the box be moving by the time it reaches the bottom of the slide?

2. Using what you know about work and energy so far, explain why any object that has a negative net work done on it (i.e., the total work done on the object by all forces is negative) MUST always be slowing down. (Recall the equation that links work and energy together.)

Explanation / Answer

1)total height =12msince no friction so no energy loss

so kinetic energy = potential energy

1/2*m*v2=m g h

v=(2*9.81*12)0.5=15.4m/s

2)When work done is negative then this emplies that the work is done in the opposite direction of movement,when movement is restricted by work in opposite direction, so the body slows down,as decelleration acting on body decellerates it.

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