The shot put is a track-and-field event in which athletes throw a heavy ball - t

Question

The shot put is a track-and-field event in which athletes throw a heavy ball - the shot - as far as possible. The best athletes can throw the shot as far as 23m . Athletes who use the "glide" technique push the shot outward in a reasonably straight line, accelerating it over a distance of about 2.0m . What acceleration do they provide to the shot as they push on it? Assume that the shot is launched at an angle of 37?, a reasonable value for an excellent throw. You can assume that the shot lands at the same height from which it is thrown; this simplifies the calculation considerably, and makes only a small difference in the final result.

Explanation / Answer

Here ,

let the speed of launch is u

range , R = u^2 * sin(theta * 2)/g

23 = u^2 * sin(2 * 37)/9.8

for u

u = 15.31 m/s

Now , let the acceleration is a

v^2 - u^2 = 2 * a * d

15.31^2 = 2 * 2 * a

a = 58.6 m/s^2

the acceleration of the ball is 58.6 m/s^2

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