The circuit drawn below has no charge on the capacitor for time t < 0. The switc

Question

The circuit drawn below has no charge on the capacitor for time t < 0. The switch is closed at time t=0.

The switch has just been closed (for t=0)

1) Since the capacitor was just closed, no charge has accumulated on the capacitor yet. What is the voltage difference (V) across the capacitor?

2) Since the batter is providing 5V total, and we just found the voltage drop across the capacitor, what is the voltage drop (V) across the resistor?

3) How much current is running through the capacitor? (Note: it is the same as the current through the resistor)

Explanation / Answer

a)

Immediately after switch is closed ,capaciotor acts as short circuit ,so volate across capaciotor is zero.

Vc=0 Volts

b)

VR=5 Volts

c)

I=V/R =5/5 =1 A

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