(Figure 1) Block 1, of mass m1 = 0.500kg , is connected over an ideal (massless

Question

(Figure 1) Block 1, of mass m1 = 0.500kg , is connected over an ideal (massless and frictionless) pulley to block 2, of mass m2, as shown. For an angle of theta() = 30.0(deg) and a coefficient of kinetic friction between block 2 and the plane of = 0.200, an acceleration of magnitude a = 0.200m/s2 is observed for block 2.

Part A

Find the mass of block 2, m2. in kg

(Figure 1) Block 1, of mass m1 = 0.500kg , is connected over an ideal (massless and frictionless) pulley to block 2, of mass m2, as shown. For an angle of theta() = 30.0(deg) and a coefficient of kinetic friction between block 2 and the plane of ¼ = 0.200, an acceleration of magnitude a = 0.200m/s2 is observed for block 2. Part A Find the mass of block 2, m2. in kg

Explanation / Answer

for m1

m1*g - T = m1*a

T = m1*(g-a) = 4.8 N

for m2

T - u*m2*g*cos30 - m2*g*sin30 = m2*a

T = m2*(u*g*cos30 + g*sin30 + a)

4.8 = m2*((0.2*9.8*cos30)+(9.8*sin30)+0.2)

m2 = 0.71 kg

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.