Given a maximum voltage of 3.9491 Volts and a minimum voltage of -0.0256 Volts,

Question

Given a maximum voltage of 3.9491 Volts and a minimum voltage of -0.0256 Volts, then what is half the maximum voltage value? 1/2 Maximum Voltage Value = ____Volts.

8. Let's say you measure t1/2 to be 0.0121 seconds and the resistance in the circuit is 103 Ohms. Then what is the capacitance in micro Farads? Capacitance = ___micro Farads.

9. Given t1/2 to be 0.0121 seconds, how long should it take to reach 93.75% of maximum charge?

time=__ seconds.

10. What would be the maximum charge in Coulombs if you have 4 volts and a capacitor of 330 micro Farads?

q = ___Coulombs.

Explanation / Answer

8. The quantity t1/2=? ln 2 is called the half-life of an exponential decay, where ?=RC is the time constant in an RC circuit.

C= 0.0121/( (ln2) *103)

= 0.016948 micro Farads

9. t1/2=? ln 2 ==> ? = 0.0121/ ln(2) where ?=RC

  ? =  0.0175 s

q= qo(1- e-(t/?) )

q/qo = (1- e-(t/?)  ) = 0.9375

t = 0.0485 s

10. qmax =cV

= 330*10-6 *4

= 1.32 mCoulomb

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