T vertical = ____ N (b) Now, the same spider sits motionless in the middle of a
ID: 1280365 • Letter: T
Question
Tvertical= ____ N
(b) Now, the same spider sits motionless in the middle of a (nearly) horizontal strand of spiderweb, as shown in the figure below. The strand sags at an angle of 10.0 below the horizontal. Calculate the tension in this (nearly) horizontal strand.
Tnew = _______
Compare this with the tension in the vertical strand that you found in part (a) (find their ratio).
Tvertica=
2. (a) A block of mass m = 8.50 kg is suspended as shown in the diagram below. Assume the pulley to be frictionless and the mass of the strings to be negligible. If the system is in equilibrium, what will be the reading of the spring scale in newtons? _____ N
(b) Two blocks each of mass m = 8.50 kg are connected as shown in the diagram below. Assume the pulley to be frictionless and the mass of the strings to be negligible. If the system is in equilibrium, what will be the reading of the spring scale in newtons?
_____ N
(c) A block of mass m = 8.50 kg is in equilibrium on an incline plane of angle ? = 29.0 when connected as shown in the diagram below. Assume the mass of the strings to be negligible. If the system is in equilibrium, what will be the reading of the spring scale in newtons?
______ N
Tvertica=
2. (a) A block of mass m = 8.50 kg is suspended as shown in the diagram below. Assume the pulley to be frictionless and the mass of the strings to be negligible. If the system is in equilibrium, what will be the reading of the spring scale in newtons? _____ N
(b) Two blocks each of mass m = 8.50 kg are connected as shown in the diagram below. Assume the pulley to be frictionless and the mass of the strings to be negligible. If the system is in equilibrium, what will be the reading of the spring scale in newtons?
_____ N
(c) A block of mass m = 8.50 kg is in equilibrium on an incline plane of angle ? = 29.0 when connected as shown in the diagram below. Assume the mass of the strings to be negligible. If the system is in equilibrium, what will be the reading of the spring scale in newtons?
______ N
Explanation / Answer
1a) 5.886x10^-4 N
1b) 1.695x10^-8 N
1c) ratio = 2.879
2a) 83.385 N
2b) 166.77 N
2c) 40.425 N
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