A 2300 kg truck has put its front bumper against the rear bumper of a 2500 kg SU

Question

A 2300 kg truck has put its front bumper against the rear bumper of a 2500 kg SUV to give it a push. With the engine at full power and good tires on good pavement, the maximum forward force on the truck is 18,000 N.

A)

What is the maximum possible acceleration the truck can give the SUV?

Express your answer to two significant figures and include the appropriate units.

B)

At this acceleration, what is the force of the SUV's bumper on the truck's bumper?

Express your answer to two significant figures and include the appropriate units.

Explanation / Answer

(2300+2500) a = 18000

a = 3.75 m/s^2 = 3.7 m/s^2 (for 2 significant digits)

2500*3.75 = 9375 N ( force exerted)   

for 2 significant digits = 93 N

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