A 400.0-m -wide river flows from west to east at 30.0 m/min . Your boat moves at

Question

A 400.0-m -wide river flows from west to east at 30.0 m/min . Your boat moves at 110m/min relative to the water no matter which direction you point it. To cross this river, you start from a dock at point A on the south bank. There is a boat landing directly opposite at point B on the north bank, and also one at point C , 75.0 m downstream from B.

Where on the north shore will you land if you point your boat perpendicular to the water current?

What distance will you have traveled?

If you initially aim your boat directly toward point C   and do not change that bearing relative to the shore, where on the north shore will you land?

To reach point C   at what bearing must you aim your boat?

How long will it take to cross the river?

I have no idea how to do this. If you need me to add point to this just comment. Show me how you do this problem.

Explanation / Answer

a) It will take 4 mins to get across the river. During that time the river will carry you downstream 120m. You will land 120 m East of B

b) Distance traveled is found using Pythagoras = ?(400^2 + 120^2) = 418 m

c) 4 minutes

d) This is question 2. You are right - the question is confusing. I think some bits are missing. A lot of the information they have given you has not been used.

e) the observer will see you cove 418 m in 4 minutes, so your speed is 104.5 m/min

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